Mean value theorem (divided differences)

In mathematical analysis, the mean value theorem for divided differences generalizes the mean value theorem to higher derivatives.[1]

Statement of the theorem

For any n + 1 pairwise distinct points x0, ..., xn in the domain of an n-times differentiable function f there exists an interior point

ξ ( min { x 0 , , x n } , max { x 0 , , x n } ) {\displaystyle \xi \in (\min\{x_{0},\dots ,x_{n}\},\max\{x_{0},\dots ,x_{n}\})\,}

where the nth derivative of f equals n ! times the nth divided difference at these points:

f [ x 0 , , x n ] = f ( n ) ( ξ ) n ! . {\displaystyle f[x_{0},\dots ,x_{n}]={\frac {f^{(n)}(\xi )}{n!}}.}

For n = 1, that is two function points, one obtains the simple mean value theorem.

Proof

Let P {\displaystyle P} be the Lagrange interpolation polynomial for f at x0, ..., xn. Then it follows from the Newton form of P {\displaystyle P} that the highest order term of P {\displaystyle P} is f [ x 0 , , x n ] x n {\displaystyle f[x_{0},\dots ,x_{n}]x^{n}} .

Let g {\displaystyle g} be the remainder of the interpolation, defined by g = f P {\displaystyle g=f-P} . Then g {\displaystyle g} has n + 1 {\displaystyle n+1} zeros: x0, ..., xn. By applying Rolle's theorem first to g {\displaystyle g} , then to g {\displaystyle g'} , and so on until g ( n 1 ) {\displaystyle g^{(n-1)}} , we find that g ( n ) {\displaystyle g^{(n)}} has a zero ξ {\displaystyle \xi } . This means that

0 = g ( n ) ( ξ ) = f ( n ) ( ξ ) f [ x 0 , , x n ] n ! {\displaystyle 0=g^{(n)}(\xi )=f^{(n)}(\xi )-f[x_{0},\dots ,x_{n}]n!} ,
f [ x 0 , , x n ] = f ( n ) ( ξ ) n ! . {\displaystyle f[x_{0},\dots ,x_{n}]={\frac {f^{(n)}(\xi )}{n!}}.}

Applications

The theorem can be used to generalise the Stolarsky mean to more than two variables.

References

  1. ^ de Boor, C. (2005). "Divided differences". Surv. Approx. Theory. 1: 46–69. MR 2221566.
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