1867 Rhode Island gubernatorial election

1867 Rhode Island gubernatorial election

April 3, 1867

Nominee Ambrose Burnside Lyman Pierce Party Republican Democratic Popular vote 7,372 3,178 Percentage 69.84% 30.11%

County results Burnside:      60–70%      70–80%

Governor before election Ambrose Burnside Republican Elected Governor Ambrose Burnside Republican

The 1867 Rhode Island gubernatorial election was held on April 3, 1867, in order to elect the governor of Rhode Island. Incumbent Republican governor Ambrose Burnside won re-election against Democratic nominee Lyman Pierce in a rematch of the previous election.^[1]

General election

On election day, April 3, 1867, incumbent Republican governor Ambrose Burnside won re-election by a margin of 4,194 votes against his opponent Democratic nominee Lyman Pierce, thereby retaining Republican control over the office of governor. Burnside was sworn in for his second term on May 4, 1867.^[2]

Results

Rhode Island gubernatorial election, 1867

Party		Candidate	Votes	%
	Republican	Ambrose Burnside (incumbent)	7,372	69.84
	Democratic	Lyman Pierce	3,178	30.11
		Scattering	6	0.05
Total votes			10,556	100.00
	Republican hold

References

1. "Ambrose Burnside". National Governors Association. Retrieved 2024-04-07.
2. "RI Governor". ourcampaigns.com. July 26, 2005. Retrieved 2024-04-07.